08删除链表的倒数第n个节点

删除链表的倒数第n个节点

给你一个链表,删除链表的倒数第 n 个结点,并且返回链表的头结点。

示例 1:

img

输入:head = [1,2,3,4,5], n = 2
输出:[1,2,3,5]

示例 2:

输入:head = [1], n = 1
输出:[]

示例 3:

输入:head = [1,2], n = 1
输出:[1]

提示:

  • 链表中结点的数目为 sz
  • 1 <= sz <= 30
  • 0 <= Node.val <= 100
  • 1 <= n <= sz
public class ListNode {
  int val;
  ListNode next;

  ListNode() {
  }

  ListNode(int val) {
    this.val = val;
  }

  ListNode(int val, ListNode next) {
    this.val = val;
    this.next = next;
  }
}
public ListNode removeNthFromEnd(ListNode head, int n) {
  ListNode dummy = new ListNode(0,head);
  ListNode first = head;
  ListNode second = dummy;
  for (int i = 0; i < n; i++) {
    first = first.next;
  }

  while (first!=null){
    first = first.next;
    second = second.next;
  }

  second.next = second.next.next;
  return dummy.next;

}

08删除链表的倒数第n个节点
https://jiajun.xyz/2026/02/07/算法/07链表/08删除链表的倒数第n个节点/
作者
Lambda
发布于
2026年2月7日
许可协议